Technical Analyst Who Predicted Q1 Rise Confirms: “VeChain Is Breaking Out”

Last Updated on 18 March 2021 by CryptoTips.eu


Jeroen Kok

Jeroen is one of the lead copywriters on Cryptotips.eu and discusses all recent events in the crypto market. This includes news updates, but also price analyzes and more. He developed his passion for cryptocurrency during the bull run in 2017. He has learned a lot since then. The combination of cryptocurrency and creative writing is perfect for Jeroen and an excellent way to share his knowledge with a wide audience. Find me on LinkedIn / [email protected]

Renowned technical analyst and crypto investor Justin Bennett said at the end of last year that VeChain was ready for a breakout and was soon followed in his opinion by Dutch analyst Michael Van De Poppe. The Amsterdam based trader who has become Cointelegraph’s go-to guy for technical analysis.

With those two giving it their blessing and VeChain at that time trading at $0,019 only, CryptoTips felt well enough to repeat their analysis, which indeed came true in January and February.

By now, Justin Benett, who’s been calling tops and bottoms for VeChain rather correctly in the past months, has gone on a tweetstorm in the past couple of hours as he foresees the small altcoin to break out of a descending channel and shortly aim for a new all time high. He stated:

$VET is breaking out. 0.075 and 0.10 could come faster than you think.

VeChain has already gained 36% in the past week after Norwegian aluminum giant Norsk Hydro became the last global company to cooperate with the small altcoin in order to track the authenticity of its products.

Hydro released a press release explaining the launch of the DNV blockchain (which uses the VeChain Thor public blockchain) Tag. Trace. Trust. to provide evidence of its sustainability claims for the aluminium it produces.

Bennett, who according to Lunarcrush’s social media metrics is the biggest influencer of VeChain’s price, said just moments ago:

$VET has tons of room to run to catch up to $ADA.